After fillings the car's fuel tank, a driver drove from P to Q and then to R. He used 2/5th portion of the fuel driving from P to Q. If she used another 7 liters to drive from Q to R and still had 1/4th of the tank left, how many liters does the tank hold?
Created: 1 year ago |
Updated: 9 months ago
best des
Let, the tank hold= x litre
P to q= 2x/5
Left= 3x/5
Q tto r = 7
Atq, 3x/5-7= x/4
3x-35/5= x/4
X= 20
Let,
The tank hold = 1 litres
So,
After driving from P to Q, the tank left,
1 - 2/5
= 3/5
Let, he used x litre to drive from Q to R.
Then,
3/5 - x = 1/4
=> 12 -20x = 5
=> 20x = 12-5 = 7
=> x = 7/20
Now,
According to the question,
7/20 means = 7
So, 1 means = (7×20)/7 = 20
So, the tank hold 20 litres.
Ans. 20
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